Question

Suma a 3 numere este 606.Sa se afle numerele stiind ca primul este jumatate din celorlalte doua iar al doilea este o treime din al treilea

Answer 1

a+b+c=606
a=(b+c) :2
b= 1/3×c =c/3
=>a=(c/3+c) :2
(c/3+c) :2+c/3+c=606
4c/3÷2+4c/3=606
4c/3×1/2+4c/3=606
2c/3+4c/3=606
6c/3=606
c=606:6/3
c=606:2/1
c=606×1/2
c=303

b= c/3=303/3=101
a=(b+c) :2= 101+303):2= 404:2=202

Answer 2

$a + b + c = 606$

$a = \frac{b + c}{2}$

$b = \frac{c}{3}$

$a = \frac{ \frac{c}{3} + c }{2}$

$2a = \frac{c}{3} + c \: | \times 3$

$6a = c + 3c$

$6a = 4c$

$a = \frac{4c}{6}$

$a = \frac{2c}{3}$

$\frac{2c}{3} + \frac{c}{3} + c = 606 \: | \times 3$

$2c + c + 3c = 1818$

$6c = 1818$

$c = \frac{1818}{6}$

$c = 303$

$a = \frac{2c}{3}$

$a = \frac{2 \times 303}{3}$

$a = 2 \times 101$

$a = 202$

$b = \frac{c}{3}$

$b = \frac{303}{3}$

$b = 101$