Question

suma a 3 numereeste 135 impartind primele2 numere la al treilea obtinem caturile 12si 31,iar resturile 1sirespectiv 2.determinati numerele

Answer 1

[tex]a+b+c=135\\ a:c=12,r=1=\ \textgreater \ a=12c+1\\ b:c=31,r=2=\ \textgreater \ b=31c+2\\ Inlocuim:\\ 12c+1+31c+2+c=135\\ 44c+3=135\\ 44c=132=\ \textgreater \ c=3\\ a=12*3+1=\ \textgreater \ a=37\\ b=31*3+2=\ \textgreater \ b=95[/tex]