Question

Suma a 4 nr consecutive este egala cu 58.Aflati nr.

Answer 1

a+a+1+a+2+a+3=58
4a+6=58 |- 6
4a=52 |:4
a=13
13+1=14
13+2=15
13+3=16
Cele 4 nr.sunt: 13,14,15,16

Answer 2

x-primul nr.
x+1-al II nr.
x+2-al III nr
x+4-al IV nr
x+(x+1)+(x+2)+(x+3)=58
4x+6=58⇒4x=58-6
4x=52
x=52/4
x=13
nr.consecutive sunt;13, 14 ,15, 16