Question

suma a 4 nr consecutive pare este 132 afla nr

Answer 1

a+a+1+a+2+a+3=132
4*a+6=132
4*a=132-6
a=126:4
a=31,5=>a+1=32,5;a+2=33,5;a+3=34,5

Answer 2

                              2                     2     2                    2    2    2
|______|______|___|______|___|___|______|___|___|___|  ==> 132

132-12=120
120:4=30(primul numar)
30+2=32(al doilea numar)
30+2+2=34(al treilea numar)
30+2+2+2=36(al patrulea numar)

Coronita plss!!! :((