Question

suma a 4 nr consecutive pare este 740 aflanr

Answer 1

2k-2  +  2k  + 2k+2  +2k+4 = 740
8k+4 = 740
8k = 736
k = 736:8 = 92
2k-2 = 184-2 = 182
2k = 184
2k+2 = 186
2k+4 = 188
Verificare: 182+184+186+188 = 740, ok.

Answer 2

I.  (.....)               
II. (.....)(2)                   } 740
III.(.....)(2)(2)      
IV.(.....)(2)(2)(2) 

740-(2+2+2+2+2+2)=740-12=728

4 segmente egale 

728:4=182 -I.
182+2=184-II.
184+2=186 -III.
186+2=188-IV.

Verificare:182+184+186+188=740