Question

suma a 4 nr este 503. Daca din fiecare se scade acelas numar se obtin nr. 53, 79, 91 si 80. Care sunt cele 4 nr??

Answer 1

53+79+91+80=303.
503-303=200
200/4=50
Rezulta ca numerele sunt 103,129,141 si 130

Answer 2

A+B+C+D=503
A-E=53->A=53+E
B-E=79->B=79+E
C-E=91->C=91+E
D-E=80->D=80+E
E-numarul care se scade
53+E+79+E+91+E+80+E=503
53+79+91+90+4E=503
4E+303=503
4E=503-303
4E=200
E=200:4
E=50
A-50=53->A=53+50=103
B-50=79->B=79+50=129
C-50=91->C=91+50=141
D-50=80->D=80+50=130