Question

Suma a 4 numere consecutive este 54.Aflati numerele..helpp

Answer 1

n
n+1
n+2
n+3

n+n+1+n+2+n+3=54
4n+6=54
4n=54-6
4n=48
n=12

Numerele sunt 12, 13, 14, 15.

Answer 2

r/e:
1)54-6=48
2)48 : 4=12(1-numar)
3)12+1=13(2-numar)
4)12+2=14(3-numar)
5)12+3=15(4-numar)
V:12+13+14+15=54
R/s12(1-numar)
      13(2-numar)
      14(3-numar)
       15(4-numar)