Question

suma a 4 numere este 42.Stiind ca primele 3 sunt consecutive pare,cu suma 30, identifica-le

Answer 1

a+(a+2)+(a+4)+b=42
30+b=42
b=42-30
b=12
3a+2+4=30
3×a=30-2-4
3×a=24
a=24:3
a=8
8+(8+2)+(8+4)=42
8+10+12+12=42
r:a=8
c=10
d=12
b=12