Question

suma a 4 numere naturale consecutive esre 50, aflati numerele

Answer 1

deci 
primul nr n
al doilea nr n+1
al treilea n+2
al patrulea n+3
n+n+1+n+2+n+3 = 50
4n +6 =50
4n =50-6
4n =44
n=44:4
n=11
deci
primul n este 11,al doilea 12,al treilea 13 si al patrulea 14

Answer 2

x+1+x+2+x+3+x=50
4x+1+2+3=50
4x+1+2=50-3
4x+1+2=47
4x+1=47-2
4x+1=45
4x=45-1
4x=44
x=44:4
x=9
1nr.=9
2nr.=9+1=10
3nr.=9+2=11
4nr.+9+3=12