Question

Suma a 4 numere naturale consecutive este 114.Determinați numerele

Answer 1

a+(a+1)+(a+2)+(a+3)=114
4a+6=114
4a=108
a=27
a+1=27+1=28
a+2=27+2=29
a+3=27+3=30
Numerele sunt: {27, 28, 29, 30}

Answer 2

notam a,b,c,d cele 4 nr naturale consecutive 
a=a
b=a+1
c=a+1+1=a+2
d=a+1+1+1=a+3 
a+b+c+d= 114
 
4a+6= 114
4a= 114-64
a= 108
a= 108:4a= 27
b= 27+1⇒b= 28
c= 27+2⇒ c= 29 d= 27+3 ⇒ d= 30