Question

Suma a 4numere consecutive este 618.determinati numerele

Answer 1

a+b+c+d=618
a |-----|
b |-----|1|
c |-----|1|1|
d |-----|1|1|1| } 618.

618 - (1+1+1+1+1+1 )= 618- 6 = 612 (4 segmente egale cu a)
612 : 4=153 (a)
153 + 1=154 (b)
153+1+1 = 155 (c)
153 +1+1+1= 156 (d)
Proba : 153+154+155+156=618.

Answer 2

x=primul nr
x+1=al doilea nr
x+2=al treilea nr
x+3=al patrulea nr
x+x+1+x+2+x+3=618
4x+6=618
4x=618-6
4x=612
x=153(primul nr)
153+1=154(al doilea nr)
153+2=155(al treilea nr)
153+3=156(al patrulea nr)