Question

suma a 5 nr consecutive este dif nr 397 si 327

Answer 1

a+(a+1)+(a+2)+(a+3)+(a+4)=397-327
5a+10=70
5a=70-10
5a=60
a=60:5
a=12
12+(12+1)+ (12+2)+(12+3)+(12+4)=70
12+13+14+15+16=70