Question

Suma a 5 nr.este 40.Primele trei sunt nr.pare consecutive.Ultimele doua sunt nr. impare si daca le adunam obtinem 16.Care sunt cele 5 numere ?

Answer 1

$x+y+z+t+s=40 \\ y=x+2 \\ z=y+2=x+4 \\ t+s=16 \\ x+x+2+x+4+16=40 \\ 3x+22=40 \\ 3x=40-22=18 \\ x=\frac{18}{3} \\ \boxed{\bold{x=6}} \\ y=x+2=6+2 \\ \boxed{\bold{y=8}} \\ z=y+2=8+2 \\ \boxed{\bold{z=10}} \\ \boxed{\bold{t=13}} \\ \boxed{\bold{s=3}}$