Question

suma a 5 numere consecutive este 40.cel din mijloc este?

Answer 1

a+b+c+d+e=40

a |-|
b |-|+1
c|-|+2
d|-|+3
e|-|+4
1+2+3+4=10
40-10=30(numarul ramas)
30:5=6(a)
6+1=7(b)
6+2=8(c)
6+3=9(d)
6+4=10(e)
V:a+b+c+d+e=40
6+7+8+9+10=40

Answer 2

1 |—|
+1
2 |—|---|
+2
3 |—|---| 40 suma
+3
4 |—|---|
+4
5 |—|---|
1+1+1+1+1=5. (parti egale)
1+2+3+4=10 (diferenta dintre cele 5 nr)
40-10=30. (suma partilor egale)
30:5=6. (1 nr )
6+1=7. (2)
7+1=8. (3)
8+1=9 (4)
9+1=10 (5)
R:6;7;8;9;10
V: 6+7+8+9+10=40