Question

Suma a 5 numere consecutive pare este egala cu diferenta numerelor 397 si 327 .Care sunt numerele

Answer 1

A+b+c+d+e=397-327. A+b+c+d+e=70. A,b,c,d si e sunt numere consecutive pare adica din doi in doi. A|-----|. B|-----|2|. C|-----|2|2|. D|-----|2|2|2|. E|-----|2|2|2|2|. 70-2x10=70-20=50. 50:5=10(a). 10+2=12(b). 12+2=14(c). 14+2=16(d). 16+2=18(e). Raspuns: a=10, b=12, c=14, d=16, e=18.

Answer 2

397-327=70(suma)
notez x- nr 1
x+2- nr 2
x+4- nr 3
x+6- nr 4
x+8- nr 6
x+x+2+x+4+x+6+x+8
=70
5x=70-20
5x=50
x=50:5
x=10
x+2=10+2=12
x+4=10+4=14
x+6=10+6=16
x+8=10+8=18
10,12,14,16,18 numerele
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