Question

suma a 5 numere naturale consecutive 5% din 1900 . sa se afle numerele

Answer 1

(a-2)+(a-1)+a+(a+1)+(a+2)=5%1900

5a=(5/100)x1900

5a=5x19

a=19

Numerele sunt: 17,18,19,20,21

Answer 2

[tex]a+b+c+d+e=x\\ x= \frac{5}{100} *1900\\ x=95\\ b=a+1\\ c=a+2\\ d=a+3\\ e=a+4\\ a+a+1+a+2+a+3+a+4=95\\ 5a=95-10\\ a= \frac{85}{5} \\ a=17\\ b=18\\ c=19\\ d=20\\ e=21\\[/tex]