Question

Suma a 5 numere naturale consecutive se imparte la 21 si se obtine catul 9 si restul 6.
Determinati cele 5 numere.

Answer 1

x= I nr

x + 1 = II nr

x +2 = III nr

x + 3 = IV nr

x + 4 = V nr

( x + x + 1 +x + 2 +x + 3 + x + 4) : 21 = 9 rest 6

5x + 10 = 21 x 9 + 6

5x + 10 = 195

5x = 195 - 10

5x = 185

x = 185 : 5

x = 37

numerele sunt : 37, 38, 39, 40 si 41