Question

Suma a 7 nr naturale impare consecutive este 119. Aflati nr.       ALGEBRIC

Answer 1

a+a+2+a+4+ a+6+a+8+a+10+a+12=119
7a+42=119
7a=77
a=77:7
a=11

Answer 2

$a+a+2+a+4+a+6+a+8+a+10+a+12=119 \\ \\ 7a+42=119 \\ \\ 7a=77 \\ \\ \boxed{a=11} \\ \\ a+2=11+2=13 \\ a+4=11+4=15 \\ a+6=11+6=17 \\ a+8=11+8=19 \\ a+10=11+10=21 \\ a+12=11+12=23 \\ \\ \boxed{R: 11,13,15,17,19,21,23}$