Question

suma a 7 numere consecutive este35210

Answer 1

5027 + 5028+5029+5030+5031+5032+5033=35210

Answer 2

      
$x =numarul\;din\;mijloc\; (al\;patrulea) \\ (x-3)+(x-2)+(x-1)+x+(x+1)+(x+2)+(x+3)=35210 \\ x-3+x-2+x-1+x+x+1+x+2+x+3=35210 \\ 7x=35210 \\ x= \frac{35210}{7}=5030 \\ nr_1=x-3=5030-3= \boxed{5027} \\ nr_2=x-2=5030-2= \boxed{5028} \\ nr_3=x-1=5030-1= \boxed{5029} \\ nr_4=x=\boxed{5030} \\ nr_5=x+1=5030+1= \boxed{5031} \\ nr_6=x+2=5030+2= \boxed{5032} \\ nr_7=x+3=5030+3= \boxed{5033}$