Question

suma a 7 numere consecutive pare este de 8 ori mai mare decat primul numar si cu 294 mai mare decat acesta.afla numerele

Answer 1

a + a + 2 +a + 4 + a + 6 +a + 8 + a + 10 + a + 12 = 8 * a = 294 + a
7a - 8a = - 42
a = 42
a + 2 = 44
a + 4 = 46
a + 6 = 48
a + 8 = 50
a + 10 = 52
a + 12 = 54
294 + 42 = 336
42 + 44 + 46 + 48 + 50 + 52 + 54 = 336

Answer 2

  a  |--------------|
  b  |--------------|+2
  c  |--------------|+2+2
  d  |--------------|+2+2+2
  e  |--------------|+2+2+2+2
  f  |---------------|+2+2+2+2+2
  g |---------------|+2+2+2+2+2+2
a+b+c+d+e+f+g=294+a
a+b+c+d+e+f+g=8a
7a+21=294+a=8a
desen    problema
 a=42
 b=44
 c=46
 d=48
 e=50
 f=52 
 g=54
suma=a+294=336