Question

suma a cinci nr consecutive e 200.care sunt nr?

Answer 1

a |----------|
b |----------|1|
c |----------|1|1|
d |----------|1|1|1|
e |----------|1|1|1|1|      } 200.

200 - ( 1+1+1+1+1+1+1+1+1+1) = 200 - 10 = 190 ( 5 segmente egale)
190 : 5 = 38 (a)
38 +1 = 39 (b)
38 +1+1 = 40 (c)
38 +1+1+1 = 41 (d)
38 +1+1+1+1 = 42 (e)
Verificam: 38+39+40+41+42 = 200.