Question

Suma a cinci nr. Consecutive nat se impart la 21 se obtine catul 9 si restul 6

Answer 1

D=CxI+R
Pornim de la relatie:

6+9x21=6+189=195 (Un nr.)
Numerele sunt : 195,194,193,192,191

Answer 2

a;b;c;d;e=> 5 numere consecutive 
a+b+c+d+e :21=9 rest 6
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aflati numerele

a+b+c+d+e=21*9+6
a+b+c+d+e=189+6
a+b+c+d+e=195

195:5-(1+1)=a
a=39-2
a=37....=> b=38; c=39; d=40; e=41

37+38+39+40+41=21*9+6
195=195

195:21=9 rest 6