Question

suma a cinci nr. naturale consecutive e 75 . Aflti nr.

Answer 1

a
a+1
a+2
a+3
a+4

a+a+1+a+2+a+3+a+4=75
5a=75-10
5a=65 =>a=13
Numerele sunt 13, 14, 15, 16, 17.

Answer 2

Fie a,b,c,d,e cele 5 numere.
Fiind consecutive, avem relatiile:
b=a+1;
c=a+2;
d=a+3;
e=a+4;(consideram a-numarul cel mai mic). Obtinem

a+a+1+a+2+a+3+a+4=75 -> 5a+10=75 -> 5a=65-> a=13;b=14;c=15;d=16;e=17;