Question

Suma a cinci numere consecutive se împarte la 21 si se obtine catul 9 si restul 6 Determinati cele cinci nr

Answer 1

salut!
a,b,c,d,e- nr. consecutive
a+b+c+d+e=S
S:21=9 rest 6=>S=21×9+6=189+6=195
b=a+1
c=a+2
d=a+3
e=a+4
_______
a,b,c,d=?
_______
a+a+1+a+2+a+3+a+4=195
5a=185
a=37
b=37+1=38
c=37+2=39
d=37+3=40
e=37+4=41

Answer 2

a+a+1+a+2+a+3+a+4=X
X:21=9 rest 6
X=189+6
X=195
5a+10=195
5a=185
a=37
Numerele sunt :37, 38,39,40,41