Question

Suma a cinci numere este 36.Primele doua sunt consecutive impare.urmatoarele au suma 24 si sunt consecutive pare.Afla numerele.

Answer 1

24-2-4
18::3=6
6
6+2=8
6+2+2=10
ultimele 3 nr sunt
6
76+2=8
6+2+2=10

36-24=12
12-2=10
10:2=5
prim nr=5 al doilea nr=5+2=7

I=5
II=7
III=6
IV=8
V=10

Answer 2

Fie a, b, c, d, e cele 5 numere.
Cum  primele 2 sunt impare consecutive=> a=2k+1, b=2k+3.
Ultimele sunt pare consecutive=> c=2p, d=2p+2, e=2p+4, p numar natural si c+d+e=24=> 2p+2p+2+2p+4=24=> 6p+6=24=> 6p=18=> p=3=< c=6, d=8, e=10.
a+b+24=36=> 2k+1+2k+3=12=> 4k+4=12=> 4k=8=> k=2=> a= 5 si b=7