Question

Suma a cinci numere pare impare consecutive este 415. Sa se afle numerele! Prin metoda figurativă!

Answer 1

a + b+ c + d + e = 415
b = a + 2
c = b + 2
d = c + 2
e = d + 2
__________
a=? , b=? , c=? , d=? , e=?

a |_____|
b |_____| 2 |
c |_____| 2 | 2 | →415
d |_____| 2 | 2 | 2 |
e |_____| 2 | 2 | 2 | 2 |

1) 1+1+1+1+1=5 ( parti egale )
2) 2+4+6+8 = 20
3) 415-20=395 ( 5 parti egale )
4)395:5=79 ( a )
5) 79 + 2 = 81 ( b )
6) 81 + 2 = 83 ( c )
7) 83 + 2 = 85 ( d )
8) 85 + 2 = 87 ( e )