Question

suma a doua nr este 132.impartind suma nr la diferenta lor,se obtine catul 5 si restul 12.care sunt nr?metoda grafica va rog!!!

Answer 1

I---------------------------------------I a
         b                      a-b
I----------------------------I=====I

I---------------------------------------II----------------------------I a+b = 132
I=====II=====II=====II=====II=====I   12     (a+b) : (a-b) = 5 si rest 12    

132-12 = 120
120:5=24
132-24=108   
b=108 :2=54
a=132-54=78


prin ecuatii
a+b=132    ⇒ a=132-b
(a+b):(a-b) = 5 si rest 12
a+b = 5(a-b) + 12
a+b=5a-5b+12
4a+12=6b
4(132-b)+12=6b
528-4b+12=6b
10b=540
b=54
a=132-54=78