Question

suma a doua nr este 60 iar diferența 20 aflați numerele a) 2+4×[3-(x+2)]=6 b) (a÷5-2)×5+2=107

Answer 1

numerele sunt:40 si 20
a)2+4×[3-(x+2)]=6
2+4×(3-x-2)=6
2+4×(x-1)=6
2+4x-4=6
2+4x=6+4
4x=10-2
x=8÷4
x=2
b)(a÷5-2)×5+2=107
5a÷25-10+2=107
5a÷25-10=107-2
5a÷25=105+10
5a=115×25
a=2875÷5
a=575

Answer 2

a+b=60
a-b=20
a+b+a-b=60+20
2a=80
a=80:2=40
b=60-40=20


a) 2+4×[3-(x+2)]=6
4×[3-(x+2)]=4
3-(x+2)=1
x+2=3-1
x=2-2
x=0

b) (a÷5-2)×5+2=107
(a÷5-2)×5=105
a÷5-2=21
a÷5=23
a=23×5
a=115