Question

Suma a doua nr nat este de 6 ori mai mare decat diferența lor.Daca din nr mai mic scădem 11,se obține un nr de doua ori mai mic decat suma dintre nr mai mare si 8.Aflati cele doua nr.

Answer 1

x+y= 6 * (x-y)

y-11= (x+8) :2

x+y= 6 * (x-y) => x+y=6x-6y => y+6y=6x-x => 7y=5x =>y= $\frac{5x}{7}$

$y-11= \frac{x+8}{2}$


$\frac{5x}{7} -11=\frac{x+8}{2}$ 


$\frac{5x-77}{7}=\frac{x+8}{2} =\ \textgreater \ 2(5x-77)=7(x+8)$


$10x-154=7x+56$

$10x-7x=154+56 =\ \textgreater \ 3x=210 =\ \textgreater \ x=70$

$y= \frac{5x}{7} = \frac{5*70}{7} =5*10=\ \textgreater \ y=50$

Answer 2

a+b=6a-6b
2b-22=a+8
a,b=?

2b=a+30
b=(a+30):2
a+(a+30):2=6a-6(a+30):2
2a+30=12a-6a-180
2a+30=6a-180
-4a=-150
a=150:4=37,5
b=67,5:2=33,75
R: Numerele sunt 37,5 şi 33,75.