Question

suma a doua numere este 132. impartind suma numerelor la diferenta numerelor se obtine catul 5 si restul 12.care sunt numerele ?

Answer 1

a+b=132
[a+b]/[a-b]=5 rest 12
⇒132/[a-b]=5 rest 12
⇒a-b=[132-12]/5
⇒a-b=120/5
⇒a-b=24;
⇒a=b+24
⇒[b+24]+b=132
⇒2b=132-24
⇒2b=108
⇒b=108/2
⇒b=54;
⇒a=b+24
⇒a=54+24
⇒a=78;

Answer 2

a+b=132
132:(a-b)=5 r12
132=5(a-b)+12
132-12=5(a-b)
a-b=120;5
a-b=24
a+b+a-b=132+24
2a=156
a=156:2=78
b=78-24=54