Question

Suma a doua numere este 24 intregi si 3/8.Aflati numerele,stiind ca unul dintre ele este mai mare decat celalalt cu 3 intregi si 5/6.
REPEDE!!!!!!!!

Answer 1

$a+b=24 \frac{3}{8} =\ \textgreater \ a+b=9 \\ \\ a=b+3 \frac{5}{6} =\ \textgreater \ a=b+ \frac{5}{2} \\ \\ b+ \frac{5}{2} +b=9amplificam=\ \textgreater \ 2b+5+2b=18=\ \textgreater \ 4b=18-5=\ \textgreater \ \\ \\ =\ \textgreater \ b= \frac{13}{4} \\ \\ a= \frac{13}{4} + \frac{5}{2} amplificam=\ \textgreater \ a= \frac{23}{4} \\ \\ \\ verificare:a+b= \frac{23}{4} + \frac{13}{4} = \frac{36}{4} =9$