Question

suma a doua numere este 64 iar raportul lor este 7 supra 9 . sa se afle numerele

Answer 1

Fie a,b-doua numere

a+b=64

a/b=7/9

a=7k

b=9k

7k+9k=64

16k=64

k=64:16

k=4

a=7×4

a=28

b=9×4

b=36

Answer 2

Răspuns:

28 si 36

Explicație pas cu pas:

$a+b = 64\\\\\frac{a}{b} = \frac{7}{9} => \boxed{9a=7b}\\\\a+b = 64\:\:\:\:/*9\\\\9a+9b = 576\\\\inlocuim\:pe\: 9a\: in\: relatie \\\\7b + 9b = 576\\\\16b = 576 \\\\b = 756:16\\\\\boxed{b=36}\\\\a+36=64\\\\a=64-36\\\\ \boxed{a=28}\\\\Verificarea: 28+36=64\\\\\frac{28}{36} =\frac{7}{9}$