Question

Suma a doua numere naturale este 110.Impartind unul dintre numere la celalalt,obtinem citul 5 si rest 8.Aflati numerele.

Answer 1

a+b=110
a:b=5 rest 8⇒ a=5b+8
5b+8+b=110
6b=102
b=17
a=110-17
a=93

Answer 2

$a+b=110\\a:b=5 \ rest \ 8 \to \boxed{a=5b+8}\\********************\\5b+8+b=110\\6b+8=110 \\6b=110-8\\6b=102\\\bold{17}\\\\a+b=110\\a=110-17\\\bold{93}$