Question

Suma a doua numere naturale este 20.determina numerele stiind ca unul dintre ele este egal cu 2supra pus 3 din celalalt

Answer 1

a;b→ numere

a+b=20

a=$\dfrac{2}{3}$·b

$\dfrac{2}{3}$·b+b=20

$\dfrac{2b+3b}{3}$=20

$\dfrac{5b}{3}$=20
5b=20·3
5b=60=>b=$\dfrac{60}{5}$=12

a+12=20=>a=20-12=8

Proba

8+12=20

Answer 2

$a,b - nr.$

$a + b = 20$

$a = \frac{2}{3} \times b$

$a = \frac{2b}{3}$

$\frac{2b}{3} + b = 20 \: | \times 3$

$2b + 3b = 60$

$5b = 60$

$b = \frac{60}{5}$

$b = 12$

$a = \frac{2b}{3}$

$a = \frac{2 \times 12}{3}$

$a = \frac{24}{3}$

$a = 8$