Question

Suma a doua numere naturale este 56. Calculati numerele stiind ca raportul lor este 3/4.

Answer 1

a+b=56
a\b=3\4 a=3b\4
3b\4+b=56 aducem la acelasi numitor prin 4
3b+4b=224
7b=224
b=32
a=56-32
a=24

Answer 2

[tex]\sf a+b=56 \\ \\ \frac{a}{b}= \frac{3}{4} \\ \\ \frac{a}{3}= \frac{b}{4}=k \longrightarrow a=3k~si~b=4k \\ \\ 3k+4k=56 \\ \\ 7k=56 \\ \\ \underline{k=8} \\ \\ a=8*3 \\ \\ \boxed{\sf a=24} \\ \\ b=4*8 \\ \\ \boxed{\sf b=32}[/tex]