Question

suma a doua numere naturale este31.La impartirea lor se obtine catul 4 si restul 1 .Aflati numerele?

Answer 1

a+b=31
a:b=4 r 1
a=b*4+1
a=4b+1
4b+1+b=31
5b+1=31
5b=31-1
5b=30
b=30:5
b=6
a=4*6+1
a=24+1
a=25

Answer 2

a+b=31
a:b=4,rest 1

a=4b+1

4b+1+b=31
5b+1=31
5b=31-1
5b=30
b=30:5
b=6

a=6×4+1
a=24+1
a=25

Proba :
25+6=31
25:6=4,rest 1