Question

suma a doua numere reale este egala cu 2,(4), iar diferemta lor este 1. determinati numerele

Answer 1

x+y= 2,(4)
x-y=1  => x=1+y  am scris x in functie de y si inlolcuim in prima relatie

1+y + y =2,(4)

1+ 2y= $2 \frac{4}{9}$

2y= $2 \frac{4}{9} - 1$

2y = $[tex]\frac{22}{9}$ -1

2y = $[tex]\frac{22}{9} - \frac{9}{9}$

2y = $\frac{13}{9}$

y= $\frac{13}{9} :2$

y= $\frac{13}{9}* \frac{1}{2}$

y= $\frac{13}{18}$

x=$1+\frac{13}{18}= \frac{18}{18} + \frac{13}{18}= \frac{31}{18}$