Question

suma a n numere naturale consecutive,n mai mare sau egal cu 2,este egala cu 2019.Determinati cele n numere
repede va rog!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 1

Răspuns:

notam nr a, b,c,d,e,f........

a=2  b=a+1  c= a+2, d= a+3....

a+(a+1)+(a+2)+(a+3)+(a+4)....(a+ x)=2019

2*( 1+2+3+4+...+x+1)=

2* x*(x+1) :2 =2019

x*(x+1)= 2019     x*(x+1)= 3*673

2+3+4+5+6+7+8+9+10= 54

11+12+13+...+20= (10+1)+ (10+2)+...+(10+10)=10 *10 + (1+2+...+10)= 100+55=155

21+22+...+30= (20+1)+(20+2) +...+(20+10)= 20*10 + (1+2+...+10)=200+55=255

31+32+....+40= 300+55=355

41+42+...+50=400+55=455

51+52+...+60=500+55=555

555+455+355+255+155+54= 1829

1829+61+62+63=2015