Question

suma a patru nr consecutive este 50.aflati nr

Answer 1

Fie a, a+1, a+2, a+3 cele trei numere consecutive => a + a + 1 + a + 2 + a + 3 = 50 => 4a + 6 = 50 => 4a = 44 => a = 11 ; celelalte trei numere consecutive sunt 12, 13 si 14.
Bafta!

Answer 2

a + b + c + d = 50 
a /.../
b/.../1/
c/.../1/1/
d/.../1/1/1/ 

4p = 50- 1* 6 = 44
1p = 44 impartit la 4 
1p = 11 

a =11
b= 11+1 = 12
c= 11+2 = 13
d= 11+3=14