Question

Suma a patru nr. consecutive impare este 24. Afla nr.

Answer 1

a |___|
b |___| 2 |
→24
c |___| 2 | 2 |
d |___| 2 | 2 | 2 |

1) 1+1+1+1=4 ( parti egale )
2)2+4+6=12
3)24-12=12 ( 4 parti egale )
4) 12:4=3 ( a )
5) 3+2=5 ( b )
6) 3+4=7 ( c )
7) 3 + 6 = 9 ( d )

Answer 2

Rezolvare:

a,b,c-numerele

a+(a+2)+(a+4)+(a+6)=24
____________________

a+(a+2)+(a+4)+(a+6)=24
a+a+2+a+4+a+6=24
4a+12=24
4a=24-12
4a=12
a=3
a+2=3+2
a+2=5
a+4=3+4
a+4=7
a+6=3+6
a+6=9

Verificare : a+(a+2)+(a+4)+(a+6)= 3+5+7+9 = 24

Deci numerele cautate sunt 3 ; 5 ; 7 ; 9.