Question

Suma a patru nr nat consecutive este 50. Aflati nr

Answer 1

a + ( a +1)  + ( a + 2) + ( a + 3 ) = 50 
4a + 6 = 50 
4a = 44 
a =11 
numerele  : 11  , 12 , 13  si  14

Answer 2

x+(x+1)+(x+2)+(x+3)=50
4x+6=50
4x=50-6
4x=44
x=44÷4
x=11
x+1=12
x+2=13
x+3=14
V: 11+12+13+14=50