Question

suma a patru nr naturale consecutive e 50.afla numerele​

Answer 1

Răspuns:

a+a+1+a+2+a+3=50

4a+6=50

4a=50-6=>a=44:4=>a=11

11+1=12

11+2=13

11+3=14

nr consecutive sunt : 11,12,13,14

Answer 2

Răspuns:

A+(a+1)+(a+2)+(a+3)=50

4a+1+2+3=50

4a+6=50

4a=50-6

4a=44

a=44:4

a=11

Verificare: 11+(11+1)+(11+2)+(11+3)

11+12+13+14=50