Question

Suma a patru nr naturale consecutive este 114.Determinati nr

Answer 1

a+b+c+d=114 ,
 a=x , b=x+1 , c=x+2 , d=x+3 ,
 x+x+1+x+2+x+3=114 ,
 4x+6 = 114 4x =114-6 = 108
, x=108 : 4 ,
x = 27 , a=27 , b=28 , c=29 =d=30

Answer 2

a+(a+1)+(a+2)+(a+3) =114
4a=114 - 6⇒4a =1 08
a=27, b=a+1=28, c=a+2=29, d=a+3=30
numerele sunt (27,28,29,30)
verificare
27+28+29+20=114
114=114