Question

suma a patru nrbconsecutive pare este 132

Answer 1

x+x+2+x+4+x+6=132
4x+12=132 |-12
4x=120 |:4
x=30- primul nr.
x+2=30+2=32-al doilea nr.
x+4=30+4=34-al treilea nr.
x+6=30+6=36-al patrulea nr

Answer 2

×+×+2+×+4+×+6=132
4×=132-2-4-6
4×=120
×=120:4
×=30
×+2=32
×+4=34
×+6=36