Question

Suma a patru numere consecutive este 166 . Care sunt numerele ?

Answer 1

a; b=a+1; c=a+2; d=a+3  cele 4 numere consecutive
a+(a+1)+(a+2)+(a+3)=166
4a+6=166
4a=166-6
4a=160
a=160:4
a=40,  b=a+1=41,    c=a+2=42,   d= a+3=43

cele 4 numere consecutive a caror suma este 166 sunt:  40, 41, 42, 43

Answer 2

$Numerele~sunt:n,n+1,n+2,n+3 \\ Inlocuim~in~suma: \\ n+n+1+n+2+n+3=166 \\ 4n+6=166 \\ 4n=166-6 \\ 4n=160 \\ n=160:4 \\ n=40(primul~numar) \\ n+1=40+1=41(al~doilea~numar) \\ n+2=40+2=42(al~treilea~numar) \\ n+3=40+3=43(al~patrulea~numar)$