Question

Suma a patru numere consecutive este egala cu 58 . Aflati numerele.

Answer 1

$x+y+z+t=58 \\ y=x+1 \\ z=x+2 \\ t=x+3 \\ x+x+1+x+2+x+3=58 \\ 4x+6=58 \\ 4x=58-6 \\ 4x=52 \\ x=52:4 \\ \boxed{x=13} \\ y=13+1 \\ \boxed{y=14} \\ z=13+2 \\ \boxed{z=15} \\ t=13+3 \\ \boxed{t=16}.$