Question

Sumă a patru numere consecutive impare este 88.
Sa se afle numerele ​
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Answer 1

Răspuns:

x+1+x+3+x+5+x+7=88

4x=88-1-3-5-7

4x=72

x=72:4

x=18

18+1=19 (primul număr)

18+3=21 (al doilea număr)

18+5=23 (al treilea număr)

18+7=25 (al patrulea număr)

Probă: 19+21+23+25=88