Question

suma a patru numere este 202.Daca din fiecars numar se scade acelasi numar,se obtin numerele 25,35,42si 92.Care sunt numerele?

Answer 1

a+b+c+d=202
notam numarul care se scade cu o litera -e
avem
a-e+b-e+c-e+d-e=25+35+42+92=194
(a+b+c+d)-4e=194
202-4e=194
4e=202-194
4e=8
e=8:4
e=2
atunci adunam la
a-e=25
a-2=25
a=25+2
a=27

b-e=35
b-2=35
b=35+2
b=37

c-e=42
c-2=42
c=42+2
c=44

d-e=92
d-2=92
d=92+2
d=94
verificarea
27+37+44+94=202
CORECT

Answer 2

a-n=25   a=25+n
b-n=35  b=35+n
c-n=42    c=42+n
d-n=92    d=92+n
a+b+c+d=202
25+n+35+n+42+n+92+n=202
194+4n=202 4n=202-194=8  n=2  
a=25+2=27
b=35+2=37
c=42+2=44
d=92+2=94