Question

Suma a patru numere intregi consecutive este egala cu -2.Calculati prosusul acestor numere

Answer 1

a+(a+1)+(a+2)+(a+3) = -2 <=> 4a +6 = -2 => 4a = -8 => a = -8:4 = -2

a= -2

a+1 = -1

a+2 = 0

a+3 = 1

a(a+1)(a+2)(a+3) = (-2)x(-1)x0x1 = 0