Question

Suma a patru numere naturale consecutive este 1002 . Care sunt numerele ? Va rog mult !! ⏳

Answer 1

I /----/
II /----/1/
III/----/1/1/
IV/----/1/1/1/
1002-1-1-1-1-1-1=996
996:4(parti)=249 (primul nr)
249+1=250(al doilea nr)
250+1=251(al treilea nr)
251+1=252(al patrulea nr)

Answer 2

a+b+c+d=1002
a|----|
b|----|-1-|
c|----|-1-|-1-|
d|----|-1-|-1-|-1-|
1002-6=1996(a=b=c=
d)
1996:4=499(a)
Apoi faci +1 pana il afii pe D!!